What are the solutions to the equation x^2-14x-147=0 ?

The solutions to the equation x^2-14x-147=0 are x=21,x=-7

Find the zeros of x^2-14x-147=0

The zeros of x^2-14x-147=0 are x=21,x=-7

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x^{2} - 14 x - 147 = 0

x = 21, x = - 7

Solution steps

x^{2} - 14 x - 147 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 147 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 147) = 28

x_{1, 2} = \frac{- ( - 14 ) \pm 28}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 28}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 28}{2 \cdot 1}

x = \frac{- ( - 14 ) + 28}{2 \cdot 1} : 21

x = \frac{- ( - 14 ) - 28}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 21, x = - 7

2 x^{2} - x^{2} - 1 = 0

m^{2} - 5 m - 50 = 0

x, x^{2} + y^{2} = 9

- k^{2} - 8 = 10 k

a^{2} + 3 a - 28 = 0

What are the solutions to the equation x^2-14x-147=0 ?
The solutions to the equation x^2-14x-147=0 are x=21,x=-7
Find the zeros of x^2-14x-147=0
The zeros of x^2-14x-147=0 are x=21,x=-7