What are the solutions to the equation a^2+3a-28=0 ?

The solutions to the equation a^2+3a-28=0 are a=4,a=-7

Find the zeros of a^2+3a-28=0

The zeros of a^2+3a-28=0 are a=4,a=-7

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a^{2} + 3 a - 28 = 0

a = 4, a = - 7

Solution steps

a^{2} + 3 a - 28 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

a_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 3 + 11}{2 \cdot 1}, a_{2} = \frac{- 3 - 11}{2 \cdot 1}

a = \frac{- 3 + 11}{2 \cdot 1} : 4

a = \frac{- 3 - 11}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

a = 4, a = - 7

8 z^{2} + 5 z

x, (x - 3)^{2} + (y - 5)^{2} = 0

x^{2} + 11 x + 24 = 0

2 x^{2} - 5 x - 3 = 0

18 k^{2} = 50

What are the solutions to the equation a^2+3a-28=0 ?
The solutions to the equation a^2+3a-28=0 are a=4,a=-7
Find the zeros of a^2+3a-28=0
The zeros of a^2+3a-28=0 are a=4,a=-7