What are the solutions to the equation quadraticformula 4x^2+20x+45=0 ?

The solutions to the equation quadraticformula 4x^2+20x+45=0 are x=-5/2+sqrt(5)i,x=-5/2-sqrt(5)i

Find the zeros of quadraticformula 4x^2+20x+45=0

The zeros of quadraticformula 4x^2+20x+45=0 are x=-5/2+sqrt(5)i,x=-5/2-sqrt(5)i

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4 x^{2} + 20 x + 45 = 0

x = - \frac{5}{2} + 5 i, x = - \frac{5}{2} - 5 i

Solution steps

4 x^{2} + 20 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 45}{2 \cdot 4}

Simplify

2 0^{2} - 4 \cdot 4 \cdot 45 : 85 i

x_{1, 2} = \frac{- 20 \pm 8 5 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 8 5 i}{2 \cdot 4}, x_{2} = \frac{- 20 - 8 5 i}{2 \cdot 4}

x = \frac{- 20 + 8 5 i}{2 \cdot 4} : - \frac{5}{2} + 5 i

x = \frac{- 20 - 8 5 i}{2 \cdot 4} : - \frac{5}{2} - 5 i

The solutions to the quadratic equation are:

x = - \frac{5}{2} + 5 i, x = - \frac{5}{2} - 5 i

(x - 4)^{2} + 5 x (x - 1) = 16

1 5^{2} = 2 0^{2} + x^{2} - 2 \cdot 20 \cdot x \cdot 0.75

2 u^{2} + u - 1 = 0

s^{2} + 12 s + 400 = 0

x^{2} + 37 x = 0

What are the solutions to the equation quadraticformula 4x^2+20x+45=0 ?
The solutions to the equation quadraticformula 4x^2+20x+45=0 are x=-5/2+sqrt(5)i,x=-5/2-sqrt(5)i
Find the zeros of quadraticformula 4x^2+20x+45=0
The zeros of quadraticformula 4x^2+20x+45=0 are x=-5/2+sqrt(5)i,x=-5/2-sqrt(5)i