What are the solutions to the equation (x+5)^2-3(x+5)-10=0 ?

The solutions to the equation (x+5)^2-3(x+5)-10=0 are x=0,x=-7

Find the zeros of (x+5)^2-3(x+5)-10=0

The zeros of (x+5)^2-3(x+5)-10=0 are x=0,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 5)^{2} - 3 (x + 5) - 10 = 0

x = 0, x = - 7

Solution steps

(x + 5)^{2} - 3 (x + 5) - 10 = 0

Expand

(x + 5)^{2} - 3 (x + 5) - 10 : x^{2} + 7 x

x^{2} + 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 0 = 7

x_{1, 2} = \frac{- 7 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 7}{2 \cdot 1}, x_{2} = \frac{- 7 - 7}{2 \cdot 1}

x = \frac{- 7 + 7}{2 \cdot 1} : 0

x = \frac{- 7 - 7}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 0, x = - 7

w^{2} = 12 w

8 x^{2} + 20 x = 48

d^{2} + 34 d = 0

7 x^{2} + 29 x - 30 = 0

(x - 7)^{2} = - 64

What are the solutions to the equation (x+5)^2-3(x+5)-10=0 ?
The solutions to the equation (x+5)^2-3(x+5)-10=0 are x=0,x=-7
Find the zeros of (x+5)^2-3(x+5)-10=0
The zeros of (x+5)^2-3(x+5)-10=0 are x=0,x=-7