What are the solutions to the equation 3x^2-5x+c=0 ?

The solutions to the equation 3x^2-5x+c=0 are x=(5+sqrt(25-12c))/6 ,x=(5-sqrt(25-12c))/6

Find the zeros of 3x^2-5x+c=0

The zeros of 3x^2-5x+c=0 are x=(5+sqrt(25-12c))/6 ,x=(5-sqrt(25-12c))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 5 x + c = 0

x = \frac{5 + 25 - 12 c}{6}, x = \frac{5 - 25 - 12 c}{6}

Solution steps

3 x^{2} - 5 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 c}{2 \cdot 3}

Simplify

(- 5)^{2} - 4 \cdot 3 c : 25 - 12 c

x_{1, 2} = \frac{- ( - 5 ) \pm 25 - 12 c}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 25 - 12 c}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 25 - 12 c}{2 \cdot 3}

x = \frac{- ( - 5 ) + 25 - 12 c}{2 \cdot 3} : \frac{5 + 25 - 12 c}{6}

x = \frac{- ( - 5 ) - 25 - 12 c}{2 \cdot 3} : \frac{5 - 25 - 12 c}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 25 - 12 c}{6}, x = \frac{5 - 25 - 12 c}{6}

g^{2} = 6 0^{2} + 1 5^{2}

9 z = 10 z^{2}

- 6 + 7 x - x^{2} = 0

2 x^{2} + 2 x - 2 = 5 x

2 x^{2} + 4 x - 16 = 0

What are the solutions to the equation 3x^2-5x+c=0 ?
The solutions to the equation 3x^2-5x+c=0 are x=(5+sqrt(25-12c))/6 ,x=(5-sqrt(25-12c))/6
Find the zeros of 3x^2-5x+c=0
The zeros of 3x^2-5x+c=0 are x=(5+sqrt(25-12c))/6 ,x=(5-sqrt(25-12c))/6