What are the solutions to the equation 4-x^2=5 ?

The solutions to the equation 4-x^2=5 are x=i,x=-i

Find the zeros of 4-x^2=5

The zeros of 4-x^2=5 are x=i,x=-i

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4 - x^{2} = 5

x = i, x = - i

Solution steps

4 - x^{2} = 5

Move

4

to the right side

- x^{2} = 1

Divide both sides by

- 1

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

4 - x^{2} = 1

x^{2} + 9 = 90

x^{2} = \frac{5}{4}

x^{2} - 5.2 x = 42.24

x^{2} = 2^{2} + 5^{2}

What are the solutions to the equation 4-x^2=5 ?
The solutions to the equation 4-x^2=5 are x=i,x=-i
Find the zeros of 4-x^2=5
The zeros of 4-x^2=5 are x=i,x=-i