What are the solutions to the equation x^2=2^2+5^2 ?

The solutions to the equation x^2=2^2+5^2 are x=sqrt(29),x=-sqrt(29)

Find the zeros of x^2=2^2+5^2

The zeros of x^2=2^2+5^2 are x=sqrt(29),x=-sqrt(29)

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x^{2} = 2^{2} + 5^{2}

x = 29, x = - 29

Decimal Notation

x = 5.38516 \dots, x = - 5.38516 \dots

Solution steps

x^{2} = 2^{2} + 5^{2}

Simplify

2^{2} + 5^{2} : 29

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 29, x = - 29

3 (m - 2)^{2} = 0

2 y^{2} - 44 y + 114 = 0

4 k^{2} - 35 k - 9 = 0

(x^{2} + x) \frac{1}{3} = x^{2} - x

\frac{5}{3} s^{2} + 3 s + 1 = 0

What are the solutions to the equation x^2=2^2+5^2 ?
The solutions to the equation x^2=2^2+5^2 are x=sqrt(29),x=-sqrt(29)
Find the zeros of x^2=2^2+5^2
The zeros of x^2=2^2+5^2 are x=sqrt(29),x=-sqrt(29)