What are the solutions to the equation 5/3 s^2+3s+1=0 ?

The solutions to the equation 5/3 s^2+3s+1=0 are s=(-9+sqrt(21))/(10),s=(-9-sqrt(21))/(10)

Find the zeros of 5/3 s^2+3s+1=0

The zeros of 5/3 s^2+3s+1=0 are s=(-9+sqrt(21))/(10),s=(-9-sqrt(21))/(10)

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\frac{5}{3} s^{2} + 3 s + 1 = 0

s = \frac{- 9 + 21}{10}, s = \frac{- 9 - 21}{10}

Decimal Notation

s = - 0.44174 \dots, s = - 1.35825 \dots

Solution steps

\frac{5}{3} s^{2} + 3 s + 1 = 0

Multiply both sides by

3

5 s^{2} + 9 s + 3 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

9^{2} - 4 \cdot 5 \cdot 3 = 21

s_{1, 2} = \frac{- 9 \pm 21}{2 \cdot 5}

Separate the solutions

s_{1} = \frac{- 9 + 21}{2 \cdot 5}, s_{2} = \frac{- 9 - 21}{2 \cdot 5}

s = \frac{- 9 + 21}{2 \cdot 5} : \frac{- 9 + 21}{10}

s = \frac{- 9 - 21}{2 \cdot 5} : \frac{- 9 - 21}{10}

The solutions to the quadratic equation are:

s = \frac{- 9 + 21}{10}, s = \frac{- 9 - 21}{10}

9 x^{2} + 4 x + 10 = 0

- f (3 f - 7) = 0

(4 x - 1) (x - 1) = 8 - 2 x

(2 x)^{2} - 60 = 5

3 k^{2} - k - 2 = 0

What are the solutions to the equation 5/3 s^2+3s+1=0 ?
The solutions to the equation 5/3 s^2+3s+1=0 are s=(-9+sqrt(21))/(10),s=(-9-sqrt(21))/(10)
Find the zeros of 5/3 s^2+3s+1=0
The zeros of 5/3 s^2+3s+1=0 are s=(-9+sqrt(21))/(10),s=(-9-sqrt(21))/(10)