What are the solutions to the equation (5x-2)^2+35x-14=-12 ?

The solutions to the equation (5x-2)^2+35x-14=-12 are x=-1/5 ,x=-2/5

Find the zeros of (5x-2)^2+35x-14=-12

The zeros of (5x-2)^2+35x-14=-12 are x=-1/5 ,x=-2/5

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(5 x - 2)^{2} + 35 x - 14 = - 12

x = - \frac{1}{5}, x = - \frac{2}{5}

Decimal Notation

x = - 0.2, x = - 0.4

Solution steps

(5 x - 2)^{2} + 35 x - 14 = - 12

Expand

(5 x - 2)^{2} + 35 x - 14 : 25 x^{2} + 15 x - 10

25 x^{2} + 15 x - 10 = - 12

Move

12

to the left side

25 x^{2} + 15 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 25 \cdot 2}{2 \cdot 25}

1 5^{2} - 4 \cdot 25 \cdot 2 = 5

x_{1, 2} = \frac{- 15 \pm 5}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 15 + 5}{2 \cdot 25}, x_{2} = \frac{- 15 - 5}{2 \cdot 25}

x = \frac{- 15 + 5}{2 \cdot 25} : - \frac{1}{5}

x = \frac{- 15 - 5}{2 \cdot 25} : - \frac{2}{5}

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = - \frac{2}{5}

x^{2} + 8 x + 1 = 0

\frac{( 3 x - 7 ) ( x + 1 )}{2} = 8

x^{2} = 7 x - 10

(x - 2)^{2} = - 12

5 x^{2} - 54 x + 94 = 2 x^{2} - 5

What are the solutions to the equation (5x-2)^2+35x-14=-12 ?
The solutions to the equation (5x-2)^2+35x-14=-12 are x=-1/5 ,x=-2/5
Find the zeros of (5x-2)^2+35x-14=-12
The zeros of (5x-2)^2+35x-14=-12 are x=-1/5 ,x=-2/5