What are the solutions to the equation 5q^2-8q=35 ?

The solutions to the equation 5q^2-8q=35 are q=(4+sqrt(191))/5 ,q=(4-sqrt(191))/5

Find the zeros of 5q^2-8q=35

The zeros of 5q^2-8q=35 are q=(4+sqrt(191))/5 ,q=(4-sqrt(191))/5

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5 q^{2} - 8 q = 35

q = \frac{4 + 191}{5}, q = \frac{4 - 191}{5}

Decimal Notation

q = 3.56405 \dots, q = - 1.96405 \dots

Solution steps

5 q^{2} - 8 q = 35

Move

35

to the left side

5 q^{2} - 8 q - 35 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 5 ( - 35 )}{2 \cdot 5}

(- 8)^{2} - 4 \cdot 5 (- 35) = 2191

q_{1, 2} = \frac{- ( - 8 ) \pm 2 191}{2 \cdot 5}

Separate the solutions

q_{1} = \frac{- ( - 8 ) + 2 191}{2 \cdot 5}, q_{2} = \frac{- ( - 8 ) - 2 191}{2 \cdot 5}

q = \frac{- ( - 8 ) + 2 191}{2 \cdot 5} : \frac{4 + 191}{5}

q = \frac{- ( - 8 ) - 2 191}{2 \cdot 5} : \frac{4 - 191}{5}

The solutions to the quadratic equation are:

q = \frac{4 + 191}{5}, q = \frac{4 - 191}{5}

\frac{x}{8} + \frac{3 x ^{2}}{16} - 0.5 = 0

x^{2} + 60 x + 500 = 6000

12 y - 4 = 9 y^{2}

0 = 2 x^{2} + 5 x + 2

y = a (4 a - 5), a = 3

What are the solutions to the equation 5q^2-8q=35 ?
The solutions to the equation 5q^2-8q=35 are q=(4+sqrt(191))/5 ,q=(4-sqrt(191))/5
Find the zeros of 5q^2-8q=35
The zeros of 5q^2-8q=35 are q=(4+sqrt(191))/5 ,q=(4-sqrt(191))/5