What are the solutions to the equation 4x(x-2)-5x(x-1)=2 ?

The solutions to the equation 4x(x-2)-5x(x-1)=2 are x=-2,x=-1

Find the zeros of 4x(x-2)-5x(x-1)=2

The zeros of 4x(x-2)-5x(x-1)=2 are x=-2,x=-1

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4 x (x - 2) - 5 x (x - 1) = 2

x = - 2, x = - 1

Solution steps

4 x (x - 2) - 5 x (x - 1) = 2

Expand

4 x (x - 2) - 5 x (x - 1) : - x^{2} - 3 x

- x^{2} - 3 x = 2

Move

2

to the left side

- x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) ( - 2 )}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) (- 2) = 1

x_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 1}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 1}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 1}{2 ( - 1 )} : - 2

x = \frac{- ( - 3 ) - 1}{2 ( - 1 )} : - 1

The solutions to the quadratic equation are:

x = - 2, x = - 1

4 p^{2} - 4 p - 15 = 4, p^{2} - 4 p - 15 = 0

0.5 (x^{2} + 1) = x

- x^{2} + x + 7 = 0

x^{2} + 12 x + 36 = 0

- y^{2} = 1

What are the solutions to the equation 4x(x-2)-5x(x-1)=2 ?
The solutions to the equation 4x(x-2)-5x(x-1)=2 are x=-2,x=-1
Find the zeros of 4x(x-2)-5x(x-1)=2
The zeros of 4x(x-2)-5x(x-1)=2 are x=-2,x=-1