What are the solutions to the equation x^2-9x+17=0 ?

The solutions to the equation x^2-9x+17=0 are x=(9+sqrt(13))/2 ,x=(9-sqrt(13))/2

Find the zeros of x^2-9x+17=0

The zeros of x^2-9x+17=0 are x=(9+sqrt(13))/2 ,x=(9-sqrt(13))/2

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x^{2} - 9 x + 17 = 0

x = \frac{9 + 13}{2}, x = \frac{9 - 13}{2}

Decimal Notation

x = 6.30277 \dots, x = 2.69722 \dots

Solution steps

x^{2} - 9 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 17 = 13

x_{1, 2} = \frac{- ( - 9 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 13}{2 \cdot 1}

x = \frac{- ( - 9 ) + 13}{2 \cdot 1} : \frac{9 + 13}{2}

x = \frac{- ( - 9 ) - 13}{2 \cdot 1} : \frac{9 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 13}{2}, x = \frac{9 - 13}{2}

y, f = 3 x^{3} - 2 x y + 5 y^{2}

2 x^{2} + 11 x - 4 = 0

x = \frac{x ^{2}}{9}

x, x^{2} + y^{2} - 4 x + 2 y = b

m^{2} = - 4 m + 12

What are the solutions to the equation x^2-9x+17=0 ?
The solutions to the equation x^2-9x+17=0 are x=(9+sqrt(13))/2 ,x=(9-sqrt(13))/2
Find the zeros of x^2-9x+17=0
The zeros of x^2-9x+17=0 are x=(9+sqrt(13))/2 ,x=(9-sqrt(13))/2