What are the solutions to the equation 2x^2+11x-4=0 ?

The solutions to the equation 2x^2+11x-4=0 are x=(-11+3sqrt(17))/4 ,x=(-11-3sqrt(17))/4

Find the zeros of 2x^2+11x-4=0

The zeros of 2x^2+11x-4=0 are x=(-11+3sqrt(17))/4 ,x=(-11-3sqrt(17))/4

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2 x^{2} + 11 x - 4 = 0

x = \frac{- 11 + 3 17}{4}, x = \frac{- 11 - 3 17}{4}

Decimal Notation

x = 0.34232 \dots, x = - 5.84232 \dots

Solution steps

2 x^{2} + 11 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 (- 4) = 317

x_{1, 2} = \frac{- 11 \pm 3 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 11 + 3 17}{2 \cdot 2}, x_{2} = \frac{- 11 - 3 17}{2 \cdot 2}

x = \frac{- 11 + 3 17}{2 \cdot 2} : \frac{- 11 + 3 17}{4}

x = \frac{- 11 - 3 17}{2 \cdot 2} : \frac{- 11 - 3 17}{4}

The solutions to the quadratic equation are:

x = \frac{- 11 + 3 17}{4}, x = \frac{- 11 - 3 17}{4}

x = \frac{x ^{2}}{9}

x, x^{2} + y^{2} - 4 x + 2 y = b

m^{2} = - 4 m + 12

20 - x = x^{2}

5 x^{2} - 5 x - 60 = 0

What are the solutions to the equation 2x^2+11x-4=0 ?
The solutions to the equation 2x^2+11x-4=0 are x=(-11+3sqrt(17))/4 ,x=(-11-3sqrt(17))/4
Find the zeros of 2x^2+11x-4=0
The zeros of 2x^2+11x-4=0 are x=(-11+3sqrt(17))/4 ,x=(-11-3sqrt(17))/4