What are the solutions to the equation 18^2=12^2+x^2 ?

The solutions to the equation 18^2=12^2+x^2 are x=6sqrt(5),x=-6sqrt(5)

Find the zeros of 18^2=12^2+x^2

The zeros of 18^2=12^2+x^2 are x=6sqrt(5),x=-6sqrt(5)

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1 8^{2} = 1 2^{2} + x^{2}

x = 65, x = - 65

Decimal Notation

x = 13.41640 \dots, x = - 13.41640 \dots

Solution steps

1 8^{2} = 1 2^{2} + x^{2}

Switch sides

1 2^{2} + x^{2} = 1 8^{2}

Move

1 2^{2}

to the right side

x^{2} = 180

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 180, x = - 180

180 = 65

- 180 = - 65

x = 65, x = - 65

x^{2} - 2 x + 10 = 25

2 x^{2} - 14 x + 9 = 0

400 - x^{2} = 20 x + 100

x, 20 m^{2} = (2 x + 6 m) x

2 x^{2} = 75 - 5 x

What are the solutions to the equation 18^2=12^2+x^2 ?
The solutions to the equation 18^2=12^2+x^2 are x=6sqrt(5),x=-6sqrt(5)
Find the zeros of 18^2=12^2+x^2
The zeros of 18^2=12^2+x^2 are x=6sqrt(5),x=-6sqrt(5)