What are the solutions to the equation 1/4 (x+3)^2+6=0 ?

The solutions to the equation 1/4 (x+3)^2+6=0 are x=2sqrt(6)i-3,x=-2sqrt(6)i-3

Find the zeros of 1/4 (x+3)^2+6=0

The zeros of 1/4 (x+3)^2+6=0 are x=2sqrt(6)i-3,x=-2sqrt(6)i-3

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\frac{1}{4} (x + 3)^{2} + 6 = 0

x = 26 i - 3, x = - 26 i - 3

Solution steps

\frac{1}{4} (x + 3)^{2} + 6 = 0

Move

6

to the right side

\frac{1}{4} (x + 3)^{2} = - 6

Multiply both sides by

4

(x + 3)^{2} = - 24

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = - 24 : x = 26 i - 3

Solve

x + 3 = - - 24 : x = - 26 i - 3

The solutions to the quadratic equation are:

x = 26 i - 3, x = - 26 i - 3

2 y^{2} - 7 y = 7

0.09 x^{2} = 1

665 - 216 x + 12 x^{2} = 0

(x - 5) (x - 8) = 8

(3 n - 1) x^{2} + 7 = 4 n x

What are the solutions to the equation 1/4 (x+3)^2+6=0 ?
The solutions to the equation 1/4 (x+3)^2+6=0 are x=2sqrt(6)i-3,x=-2sqrt(6)i-3
Find the zeros of 1/4 (x+3)^2+6=0
The zeros of 1/4 (x+3)^2+6=0 are x=2sqrt(6)i-3,x=-2sqrt(6)i-3