What are the solutions to the equation 10x^2-20x-88=-8 ?

The solutions to the equation 10x^2-20x-88=-8 are x=4,x=-2

Find the zeros of 10x^2-20x-88=-8

The zeros of 10x^2-20x-88=-8 are x=4,x=-2

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10 x^{2} - 20 x - 88 = - 8

x = 4, x = - 2

Solution steps

10 x^{2} - 20 x - 88 = - 8

Move

8

to the left side

10 x^{2} - 20 x - 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 10 ( - 80 )}{2 \cdot 10}

(- 20)^{2} - 4 \cdot 10 (- 80) = 60

x_{1, 2} = \frac{- ( - 20 ) \pm 60}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 60}{2 \cdot 10}, x_{2} = \frac{- ( - 20 ) - 60}{2 \cdot 10}

x = \frac{- ( - 20 ) + 60}{2 \cdot 10} : 4

x = \frac{- ( - 20 ) - 60}{2 \cdot 10} : - 2

The solutions to the quadratic equation are:

x = 4, x = - 2

n^{2} + 6 n + 5 = 0

5 x^{2} + 5 x = - 1

x^{2} + 11 x = 28

x^{2} - 6 x = 72

x, f = I n (x^{2} + 1)

What are the solutions to the equation 10x^2-20x-88=-8 ?
The solutions to the equation 10x^2-20x-88=-8 are x=4,x=-2
Find the zeros of 10x^2-20x-88=-8
The zeros of 10x^2-20x-88=-8 are x=4,x=-2