What are the solutions to the equation factor 9x^2+12x+4=0 ?

The solutions to the equation factor 9x^2+12x+4=0 are x=-2/3

Find the zeros of factor 9x^2+12x+4=0

The zeros of factor 9x^2+12x+4=0 are x=-2/3

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9 x^{2} + 12 x + 4 = 0

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

9 x^{2} + 12 x + 4 = 0

Factor

9 x^{2} + 12 x + 4 : (3 x + 2)^{2}

(3 x + 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

The solution to the quadratic equation is:

x = - \frac{2}{3}

x^{2} - 16 - 3 x = 2 - x^{2} - 3 x

8 y^{2} - 2 y - 1 = 0

v^{2} - 9 v + 20 = 0

X^{2} + 5 X + 4 = 0

x^{2} + 39 x = 0

What are the solutions to the equation factor 9x^2+12x+4=0 ?
The solutions to the equation factor 9x^2+12x+4=0 are x=-2/3
Find the zeros of factor 9x^2+12x+4=0
The zeros of factor 9x^2+12x+4=0 are x=-2/3