What are the solutions to the equation n^2-4=0 ?

The solutions to the equation n^2-4=0 are n=2,n=-2

Find the zeros of n^2-4=0

The zeros of n^2-4=0 are n=2,n=-2

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n^{2} - 4 = 0

n = 2, n = - 2

Solution steps

n^{2} - 4 = 0

Move

4

to the right side

n^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 4, n = - 4

4 = 2

- 4 = - 2

n = 2, n = - 2

p^{2} - 8 p = 0

r, x^{2} + y^{2} + z^{2} = r^{2}

9 x^{2} - 6 a^{2} x - b^{4} + a^{4} = 0

24 x^{2} + 18 x = 0

3 x^{2} + 15 x + 2 = 0

What are the solutions to the equation n^2-4=0 ?
The solutions to the equation n^2-4=0 are n=2,n=-2
Find the zeros of n^2-4=0
The zeros of n^2-4=0 are n=2,n=-2