What are the solutions to the equation -0.25x^2-x-1=0 ?

The solutions to the equation -0.25x^2-x-1=0 are x=-2

Find the zeros of -0.25x^2-x-1=0

The zeros of -0.25x^2-x-1=0 are x=-2

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- 0.25 x^{2} - x - 1 = 0

x = - 2

Solution steps

- 0.25 x^{2} - x - 1 = 0

Multiply both sides by

100

- 25 x^{2} - 100 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 100 ) \pm ( - 100 ) ^{2} - 4 ( - 25 ) ( - 100 )}{2 ( - 25 )}

(- 100)^{2} - 4 (- 25) (- 100) = 0

x_{1, 2} = \frac{- ( - 100 ) \pm 0}{2 ( - 25 )}

x = \frac{- ( - 100 )}{2 ( - 25 )}

\frac{- ( - 100 )}{2 ( - 25 )} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

8^{2} = 2^{2} + c^{2}

\frac{w ^{2}}{3} + 21 = 48

x^{2} - 16 x = - 48

- x^{2} + 5 = 3 x^{2}

x, x^{2} - 6 x - 17 = 0

What are the solutions to the equation -0.25x^2-x-1=0 ?
The solutions to the equation -0.25x^2-x-1=0 are x=-2
Find the zeros of -0.25x^2-x-1=0
The zeros of -0.25x^2-x-1=0 are x=-2