What are the solutions to the equation solvefor x,x^2-6x-17=0 ?

The solutions to the equation solvefor x,x^2-6x-17=0 are x=3+sqrt(26),x=3-sqrt(26)

Find the zeros of solvefor x,x^2-6x-17=0

The zeros of solvefor x,x^2-6x-17=0 are x=3+sqrt(26),x=3-sqrt(26)

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x, x^{2} - 6 x - 17 = 0

x = 3 + 26, x = 3 - 26

Decimal Notation

x = 8.09901 \dots, x = - 2.09901 \dots

Solution steps

x^{2} - 6 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 17) = 226

x_{1, 2} = \frac{- ( - 6 ) \pm 2 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 26}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 26}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 26}{2 \cdot 1} : 3 + 26

x = \frac{- ( - 6 ) - 2 26}{2 \cdot 1} : 3 - 26

The solutions to the quadratic equation are:

x = 3 + 26, x = 3 - 26

4 x^{2} - 14 x = 0

(a - x)^{2} + b^{2} = 0

2 x^{2} - 90 = - 8 x

x^{2} - x + 2 = 0

x, (x + 1) (x + 2) - (x + 2) (k - 2) = 0

What are the solutions to the equation solvefor x,x^2-6x-17=0 ?
The solutions to the equation solvefor x,x^2-6x-17=0 are x=3+sqrt(26),x=3-sqrt(26)
Find the zeros of solvefor x,x^2-6x-17=0
The zeros of solvefor x,x^2-6x-17=0 are x=3+sqrt(26),x=3-sqrt(26)