What are the solutions to the equation 2x^2-90=-8x ?

The solutions to the equation 2x^2-90=-8x are x=5,x=-9

Find the zeros of 2x^2-90=-8x

The zeros of 2x^2-90=-8x are x=5,x=-9

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2 x^{2} - 90 = - 8 x

x = 5, x = - 9

Solution steps

2 x^{2} - 90 = - 8 x

Move

8 x

to the left side

2 x^{2} - 90 + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 8 x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 90 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 90) = 28

x_{1, 2} = \frac{- 8 \pm 28}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 28}{2 \cdot 2}, x_{2} = \frac{- 8 - 28}{2 \cdot 2}

x = \frac{- 8 + 28}{2 \cdot 2} : 5

x = \frac{- 8 - 28}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

x = 5, x = - 9

x^{2} - x + 2 = 0

x, (x + 1) (x + 2) - (x + 2) (k - 2) = 0

r^{2} + 490 = 0

256 c^{2} = 169

- 8 x^{2} - 16 x = 0

What are the solutions to the equation 2x^2-90=-8x ?
The solutions to the equation 2x^2-90=-8x are x=5,x=-9
Find the zeros of 2x^2-90=-8x
The zeros of 2x^2-90=-8x are x=5,x=-9