What are the solutions to the equation z^2-3z-54=0 ?

The solutions to the equation z^2-3z-54=0 are z=9,z=-6

Find the zeros of z^2-3z-54=0

The zeros of z^2-3z-54=0 are z=9,z=-6

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z^{2} - 3 z - 54 = 0

z = 9, z = - 6

Solution steps

z^{2} - 3 z - 54 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 54) = 15

z_{1, 2} = \frac{- ( - 3 ) \pm 15}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 3 ) + 15}{2 \cdot 1}, z_{2} = \frac{- ( - 3 ) - 15}{2 \cdot 1}

z = \frac{- ( - 3 ) + 15}{2 \cdot 1} : 9

z = \frac{- ( - 3 ) - 15}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

z = 9, z = - 6

3 x - 1 \geq 9 + x

∣ 4 y - 1 ∣ \geq 8

u^{2} - 23 u + 22 = 0

5 x^{3} + 10 x^{2} - 20 x - 40

(\frac{3}{4})^{- 3}

What are the solutions to the equation z^2-3z-54=0 ?
The solutions to the equation z^2-3z-54=0 are z=9,z=-6
Find the zeros of z^2-3z-54=0
The zeros of z^2-3z-54=0 are z=9,z=-6