What are the solutions to the equation x^{(2)}+11x+24=0 ?

The solutions to the equation x^{(2)}+11x+24=0 are x=-3,x=-8

Find the zeros of x^{(2)}+11x+24=0

The zeros of x^{(2)}+11x+24=0 are x=-3,x=-8

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x^{(2)} + 11 x + 24 = 0

x = - 3, x = - 8

Solution steps

x^{(2)} + 11 x + 24 = 0

Refine

x^{2} + 11 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 24 = 5

x_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 5}{2 \cdot 1}, x_{2} = \frac{- 11 - 5}{2 \cdot 1}

x = \frac{- 11 + 5}{2 \cdot 1} : - 3

x = \frac{- 11 - 5}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 3, x = - 8

5 x^{2} + 4 = 3

5 x^{2} - 1 = 3 x^{2}

x, 4 x^{2} + x y = 16

x^{2} + 7 x + 4 = 0

(x + 5)^{2} - 16 = 0

What are the solutions to the equation x^{(2)}+11x+24=0 ?
The solutions to the equation x^{(2)}+11x+24=0 are x=-3,x=-8
Find the zeros of x^{(2)}+11x+24=0
The zeros of x^{(2)}+11x+24=0 are x=-3,x=-8