What are the solutions to the equation -2x^2+9x-7=0 ?

The solutions to the equation -2x^2+9x-7=0 are x=1,x= 7/2

Find the zeros of -2x^2+9x-7=0

The zeros of -2x^2+9x-7=0 are x=1,x= 7/2

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- 2 x^{2} + 9 x - 7 = 0

x = 1, x = \frac{7}{2}

Decimal Notation

x = 1, x = 3.5

Solution steps

- 2 x^{2} + 9 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 2 ) ( - 7 )}{2 ( - 2 )}

9^{2} - 4 (- 2) (- 7) = 5

x_{1, 2} = \frac{- 9 \pm 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 9 + 5}{2 ( - 2 )}, x_{2} = \frac{- 9 - 5}{2 ( - 2 )}

x = \frac{- 9 + 5}{2 ( - 2 )} : 1

x = \frac{- 9 - 5}{2 ( - 2 )} : \frac{7}{2}

The solutions to the quadratic equation are:

x = 1, x = \frac{7}{2}

s^{2} + 3.5 s + 25 = 0

4 x^{2} - 3 = - 59

x^{2} + 2 0^{2} = 2 5^{2}

64 = \frac{v ^{2}}{5 + 19}

14 x^{2} - 31 x - 10 = 0

What are the solutions to the equation -2x^2+9x-7=0 ?
The solutions to the equation -2x^2+9x-7=0 are x=1,x= 7/2
Find the zeros of -2x^2+9x-7=0
The zeros of -2x^2+9x-7=0 are x=1,x= 7/2