What are the solutions to the equation 64=(v^2)/(5+19) ?

The solutions to the equation 64=(v^2)/(5+19) are v=16sqrt(6),v=-16sqrt(6)

Find the zeros of 64=(v^2)/(5+19)

The zeros of 64=(v^2)/(5+19) are v=16sqrt(6),v=-16sqrt(6)

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64 = \frac{v ^{2}}{5 + 19}

v = 166, v = - 166

Decimal Notation

v = 39.19183 \dots, v = - 39.19183 \dots

Solution steps

64 = \frac{v ^{2}}{5 + 19}

Switch sides

\frac{v ^{2}}{5 + 19} = 64

Multiply both sides by

5 + 19

v^{2} = 1536

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = 1536, v = - 1536

1536 = 166

- 1536 = - 166

v = 166, v = - 166

14 x^{2} - 31 x - 10 = 0

6 (x + 8) (8 x + 1) = 0

x^{2} + 14 x - 75 = - 3

9 - (\frac{x}{2})^{2} = 6 - x

x^{2} - 4 x + 1 (m + 1) = 0.8

What are the solutions to the equation 64=(v^2)/(5+19) ?
The solutions to the equation 64=(v^2)/(5+19) are v=16sqrt(6),v=-16sqrt(6)
Find the zeros of 64=(v^2)/(5+19)
The zeros of 64=(v^2)/(5+19) are v=16sqrt(6),v=-16sqrt(6)