What are the solutions to the equation 16r^2+18r+5=0 ?

The solutions to the equation 16r^2+18r+5=0 are r=-1/2 ,r=-5/8

Find the zeros of 16r^2+18r+5=0

The zeros of 16r^2+18r+5=0 are r=-1/2 ,r=-5/8

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16 r^{2} + 18 r + 5 = 0

r = - \frac{1}{2}, r = - \frac{5}{8}

Decimal Notation

r = - 0.5, r = - 0.625

Solution steps

16 r^{2} + 18 r + 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 16 \cdot 5}{2 \cdot 16}

1 8^{2} - 4 \cdot 16 \cdot 5 = 2

r_{1, 2} = \frac{- 18 \pm 2}{2 \cdot 16}

Separate the solutions

r_{1} = \frac{- 18 + 2}{2 \cdot 16}, r_{2} = \frac{- 18 - 2}{2 \cdot 16}

r = \frac{- 18 + 2}{2 \cdot 16} : - \frac{1}{2}

r = \frac{- 18 - 2}{2 \cdot 16} : - \frac{5}{8}

The solutions to the quadratic equation are:

r = - \frac{1}{2}, r = - \frac{5}{8}

(14 - b)^{3} + b^{3} = 812

10 = π r^{2}

4.9 x^{2} + 5 x - 10 = 0

- 7 x^{2} + 2 x = - 9

4 + 9 n - 3 n^{2} = 2 - n

What are the solutions to the equation 16r^2+18r+5=0 ?
The solutions to the equation 16r^2+18r+5=0 are r=-1/2 ,r=-5/8
Find the zeros of 16r^2+18r+5=0
The zeros of 16r^2+18r+5=0 are r=-1/2 ,r=-5/8