What are the solutions to the equation 4.9x^2+5x-10=0 ?

The solutions to the equation 4.9x^2+5x-10=0 are x=(5(sqrt(221)-5))/(49),x=-(5(5+sqrt(221)))/(49)

Find the zeros of 4.9x^2+5x-10=0

The zeros of 4.9x^2+5x-10=0 are x=(5(sqrt(221)-5))/(49),x=-(5(5+sqrt(221)))/(49)

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4.9 x^{2} + 5 x - 10 = 0

x = \frac{5 ( 221 - 5 )}{49}, x = - \frac{5 ( 5 + 221 )}{49}

Decimal Notation

x = 1.00674 \dots, x = - 2.02714 \dots

Solution steps

4.9 x^{2} + 5 x - 10 = 0

Multiply both sides by

10

49 x^{2} + 50 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 49 ( - 100 )}{2 \cdot 49}

5 0^{2} - 4 \cdot 49 (- 100) = 10221

x_{1, 2} = \frac{- 50 \pm 10 221}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- 50 + 10 221}{2 \cdot 49}, x_{2} = \frac{- 50 - 10 221}{2 \cdot 49}

x = \frac{- 50 + 10 221}{2 \cdot 49} : \frac{5 ( 221 - 5 )}{49}

x = \frac{- 50 - 10 221}{2 \cdot 49} : - \frac{5 ( 5 + 221 )}{49}

The solutions to the quadratic equation are:

x = \frac{5 ( 221 - 5 )}{49}, x = - \frac{5 ( 5 + 221 )}{49}

- 7 x^{2} + 2 x = - 9

4 + 9 n - 3 n^{2} = 2 - n

25 x^{2} = 0

0 = 12 x^{2} - 32 x

x^{2} - 4 x - 3 = 2

What are the solutions to the equation 4.9x^2+5x-10=0 ?
The solutions to the equation 4.9x^2+5x-10=0 are x=(5(sqrt(221)-5))/(49),x=-(5(5+sqrt(221)))/(49)
Find the zeros of 4.9x^2+5x-10=0
The zeros of 4.9x^2+5x-10=0 are x=(5(sqrt(221)-5))/(49),x=-(5(5+sqrt(221)))/(49)