What are the solutions to the equation 0=12x^2-32x ?

The solutions to the equation 0=12x^2-32x are x= 8/3 ,x=0

Find the zeros of 0=12x^2-32x

The zeros of 0=12x^2-32x are x= 8/3 ,x=0

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0 = 12 x^{2} - 32 x

x = \frac{8}{3}, x = 0

Decimal

x = 2.66666 \dots, x = 0

Solution steps

0 = 12 x^{2} - 32 x

Switch sides

12 x^{2} - 32 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

(- 32)^{2} - 4 \cdot 12 \cdot 0 = 32

x_{1, 2} = \frac{- ( - 32 ) \pm 32}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 32 ) + 32}{2 \cdot 12}, x_{2} = \frac{- ( - 32 ) - 32}{2 \cdot 12}

x = \frac{- ( - 32 ) + 32}{2 \cdot 12} : \frac{8}{3}

x = \frac{- ( - 32 ) - 32}{2 \cdot 12} : 0

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = 0

x^{2} - 4 x - 3 = 2

9 x^{2} + 6 x + 1

x + 15 = x (x - 1)

(2 x + 1) (x - 4) - 10 = 0

x, x^{2} + 7 x = 0

What are the solutions to the equation 0=12x^2-32x ?
The solutions to the equation 0=12x^2-32x are x= 8/3 ,x=0
Find the zeros of 0=12x^2-32x
The zeros of 0=12x^2-32x are x= 8/3 ,x=0