What are the solutions to the equation x^2+11x+27=-x-8 ?

The solutions to the equation x^2+11x+27=-x-8 are x=-5,x=-7

Find the zeros of x^2+11x+27=-x-8

The zeros of x^2+11x+27=-x-8 are x=-5,x=-7

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x^{2} + 11 x + 27 = - x - 8

x = - 5, x = - 7

Solution steps

x^{2} + 11 x + 27 = - x - 8

Move

8

to the left side

x^{2} + 11 x + 35 = - x

Move

x

to the left side

x^{2} + 12 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 35 = 2

x_{1, 2} = \frac{- 12 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2}{2 \cdot 1}, x_{2} = \frac{- 12 - 2}{2 \cdot 1}

x = \frac{- 12 + 2}{2 \cdot 1} : - 5

x = \frac{- 12 - 2}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 5, x = - 7

(x + 3)^{2} + (x + 4)^{2} = - x

(x - 13) (x - 5) = 13

6 n^{2} - 23 n + 20 = 0

4 x^{2} + 2 = 30

(1 + \frac{x}{2})^{2} = (1 + \frac{0.08}{4})^{4}

What are the solutions to the equation x^2+11x+27=-x-8 ?
The solutions to the equation x^2+11x+27=-x-8 are x=-5,x=-7
Find the zeros of x^2+11x+27=-x-8
The zeros of x^2+11x+27=-x-8 are x=-5,x=-7