What are the solutions to the equation -7x^2+12x=10 ?

The solutions to the equation -7x^2+12x=10 are x= 6/7-i(sqrt(34))/7 ,x= 6/7+i(sqrt(34))/7

Find the zeros of -7x^2+12x=10

The zeros of -7x^2+12x=10 are x= 6/7-i(sqrt(34))/7 ,x= 6/7+i(sqrt(34))/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 7 x^{2} + 12 x = 10

x = \frac{6}{7} - i \frac{34}{7}, x = \frac{6}{7} + i \frac{34}{7}

Solution steps

- 7 x^{2} + 12 x = 10

Move

10

to the left side

- 7 x^{2} + 12 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 7 ) ( - 10 )}{2 ( - 7 )}

Simplify

1 2^{2} - 4 (- 7) (- 10) : 234 i

x_{1, 2} = \frac{- 12 \pm 2 34 i}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 12 + 2 34 i}{2 ( - 7 )}, x_{2} = \frac{- 12 - 2 34 i}{2 ( - 7 )}

x = \frac{- 12 + 2 34 i}{2 ( - 7 )} : \frac{6}{7} - i \frac{34}{7}

x = \frac{- 12 - 2 34 i}{2 ( - 7 )} : \frac{6}{7} + i \frac{34}{7}

The solutions to the quadratic equation are:

x = \frac{6}{7} - i \frac{34}{7}, x = \frac{6}{7} + i \frac{34}{7}

- \frac{1}{8} x^{2} + x = 0

y, y^{2} = - 6 x^{2} + c

a x^{2} - (a - 5) x + 1 = 0, a

10 x^{2} - 1500 x + 180000 = 0

(4 r - 4)^{2} = 36

What are the solutions to the equation -7x^2+12x=10 ?
The solutions to the equation -7x^2+12x=10 are x= 6/7-i(sqrt(34))/7 ,x= 6/7+i(sqrt(34))/7
Find the zeros of -7x^2+12x=10
The zeros of -7x^2+12x=10 are x= 6/7-i(sqrt(34))/7 ,x= 6/7+i(sqrt(34))/7