What are the solutions to the equation -1/8 x^2+x=0 ?

The solutions to the equation -1/8 x^2+x=0 are x=0,x=8

Find the zeros of -1/8 x^2+x=0

The zeros of -1/8 x^2+x=0 are x=0,x=8

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- \frac{1}{8} x^{2} + x = 0

x = 0, x = 8

Solution steps

- \frac{1}{8} x^{2} + x = 0

Multiply both sides by

8

- x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 ( - 1 )}, x_{2} = \frac{- 8 - 8}{2 ( - 1 )}

x = \frac{- 8 + 8}{2 ( - 1 )} : 0

x = \frac{- 8 - 8}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = 0, x = 8

y, y^{2} = - 6 x^{2} + c

a x^{2} - (a - 5) x + 1 = 0, a

10 x^{2} - 1500 x + 180000 = 0

(4 r - 4)^{2} = 36

x (3 x + 7) = 6

What are the solutions to the equation -1/8 x^2+x=0 ?
The solutions to the equation -1/8 x^2+x=0 are x=0,x=8
Find the zeros of -1/8 x^2+x=0
The zeros of -1/8 x^2+x=0 are x=0,x=8