What are the solutions to the equation x(3x+7)=6 ?

The solutions to the equation x(3x+7)=6 are x= 2/3 ,x=-3

Find the zeros of x(3x+7)=6

The zeros of x(3x+7)=6 are x= 2/3 ,x=-3

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x (3 x + 7) = 6

x = \frac{2}{3}, x = - 3

Decimal Notation

x = 0.66666 \dots, x = - 3

Solution steps

x (3 x + 7) = 6

Expand

x (3 x + 7) : 3 x^{2} + 7 x

3 x^{2} + 7 x = 6

Move

6

to the left side

3 x^{2} + 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 6) = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 \cdot 3}, x_{2} = \frac{- 7 - 11}{2 \cdot 3}

x = \frac{- 7 + 11}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 7 - 11}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 3

x, f = 2 k x^{2} - 4 k x + 1

\frac{1}{3} x^{2} + 5 x + 18 = 0

2 n^{2} - 18 n = - 40

- 4 x^{2} - 2 x - 1 = 0

y, \frac{y ^{2}}{a ^{2}} + \frac{x ^{2}}{b ^{2}} = 1

What are the solutions to the equation x(3x+7)=6 ?
The solutions to the equation x(3x+7)=6 are x= 2/3 ,x=-3
Find the zeros of x(3x+7)=6
The zeros of x(3x+7)=6 are x= 2/3 ,x=-3