What are the solutions to the equation 1/3 x^2+5x+18=0 ?

The solutions to the equation 1/3 x^2+5x+18=0 are x=-6,x=-9

Find the zeros of 1/3 x^2+5x+18=0

The zeros of 1/3 x^2+5x+18=0 are x=-6,x=-9

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\frac{1}{3} x^{2} + 5 x + 18 = 0

x = - 6, x = - 9

Solution steps

\frac{1}{3} x^{2} + 5 x + 18 = 0

Multiply both sides by

3

x^{2} + 15 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 54 = 3

x_{1, 2} = \frac{- 15 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 3}{2 \cdot 1}, x_{2} = \frac{- 15 - 3}{2 \cdot 1}

x = \frac{- 15 + 3}{2 \cdot 1} : - 6

x = \frac{- 15 - 3}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = - 6, x = - 9

2 n^{2} - 18 n = - 40

- 4 x^{2} - 2 x - 1 = 0

y, \frac{y ^{2}}{a ^{2}} + \frac{x ^{2}}{b ^{2}} = 1

1.163 x^{2} - 4.44 x = 0

x, x^{2} + 5.35 x + 9.125 = 0

What are the solutions to the equation 1/3 x^2+5x+18=0 ?
The solutions to the equation 1/3 x^2+5x+18=0 are x=-6,x=-9
Find the zeros of 1/3 x^2+5x+18=0
The zeros of 1/3 x^2+5x+18=0 are x=-6,x=-9