What are the solutions to the equation completesquare x^2+5x-1=0 ?

The solutions to the equation completesquare x^2+5x-1=0 are x=(sqrt(29)-5)/2 ,x=(-sqrt(29)-5)/2

Find the zeros of completesquare x^2+5x-1=0

The zeros of completesquare x^2+5x-1=0 are x=(sqrt(29)-5)/2 ,x=(-sqrt(29)-5)/2

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x^{2} + 5 x - 1 = 0

x = \frac{29 - 5}{2}, x = \frac{- 29 - 5}{2}

Decimal Notation

x = 0.19258 \dots, x = - 5.19258 \dots

Solution steps

x^{2} + 5 x - 1 = 0

Move

1

to the right side

x^{2} + 5 x = 1

Rewrite in the form

(x + a)^{2} = b

(x + \frac{5}{2})^{2} = \frac{29}{4}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{5}{2} = \frac{29}{4} : x = \frac{29 - 5}{2}

Solve

x + \frac{5}{2} = - \frac{29}{4} : x = \frac{- 29 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{29 - 5}{2}, x = \frac{- 29 - 5}{2}

- 3 x^{2} + 6 x - 1

\frac{1}{3} x^{2} + 3 x - 4 = - 4

x, x \cdot (x - y) + y \cdot (y - z) + z \cdot (z - x) = 1

n^{2} - 12 n = - 17

6 x^{2} + 6 = - 13 x

What are the solutions to the equation completesquare x^2+5x-1=0 ?
The solutions to the equation completesquare x^2+5x-1=0 are x=(sqrt(29)-5)/2 ,x=(-sqrt(29)-5)/2
Find the zeros of completesquare x^2+5x-1=0
The zeros of completesquare x^2+5x-1=0 are x=(sqrt(29)-5)/2 ,x=(-sqrt(29)-5)/2