What are the solutions to the equation 1/3 x^2+3x-4=-4 ?

The solutions to the equation 1/3 x^2+3x-4=-4 are x=0,x=-9

Find the zeros of 1/3 x^2+3x-4=-4

The zeros of 1/3 x^2+3x-4=-4 are x=0,x=-9

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\frac{1}{3} x^{2} + 3 x - 4 = - 4

x = 0, x = - 9

Solution steps

\frac{1}{3} x^{2} + 3 x - 4 = - 4

Multiply both sides by

3

x^{2} + 9 x - 12 = - 12

Move

12

to the left side

x^{2} + 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 0 = 9

x_{1, 2} = \frac{- 9 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 9}{2 \cdot 1}, x_{2} = \frac{- 9 - 9}{2 \cdot 1}

x = \frac{- 9 + 9}{2 \cdot 1} : 0

x = \frac{- 9 - 9}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 0, x = - 9

x, x \cdot (x - y) + y \cdot (y - z) + z \cdot (z - x) = 1

n^{2} - 12 n = - 17

6 x^{2} + 6 = - 13 x

2 x^{2} + 7 x - 30 = 64 (x + 6)

6 x^{2} + 9 x - 16 = 0

What are the solutions to the equation 1/3 x^2+3x-4=-4 ?
The solutions to the equation 1/3 x^2+3x-4=-4 are x=0,x=-9
Find the zeros of 1/3 x^2+3x-4=-4
The zeros of 1/3 x^2+3x-4=-4 are x=0,x=-9