What are the solutions to the equation 6x^2+9x-16=0 ?

The solutions to the equation 6x^2+9x-16=0 are x=(-9+sqrt(465))/(12),x=(-9-sqrt(465))/(12)

Find the zeros of 6x^2+9x-16=0

The zeros of 6x^2+9x-16=0 are x=(-9+sqrt(465))/(12),x=(-9-sqrt(465))/(12)

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6 x^{2} + 9 x - 16 = 0

x = \frac{- 9 + 465}{12}, x = \frac{- 9 - 465}{12}

Decimal Notation

x = 1.04698 \dots, x = - 2.54698 \dots

Solution steps

6 x^{2} + 9 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 6 ( - 16 )}{2 \cdot 6}

9^{2} - 4 \cdot 6 (- 16) = 465

x_{1, 2} = \frac{- 9 \pm 465}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 9 + 465}{2 \cdot 6}, x_{2} = \frac{- 9 - 465}{2 \cdot 6}

x = \frac{- 9 + 465}{2 \cdot 6} : \frac{- 9 + 465}{12}

x = \frac{- 9 - 465}{2 \cdot 6} : \frac{- 9 - 465}{12}

The solutions to the quadratic equation are:

x = \frac{- 9 + 465}{12}, x = \frac{- 9 - 465}{12}

a^{2} - 8 a = - 15

10 x^{2} + 20 x = 0

30 = 0.000006 x^{2} - 0.02 x + 25

z^{2} + 6 z = 0

(x) = x^{2} + 2 x + 1

What are the solutions to the equation 6x^2+9x-16=0 ?
The solutions to the equation 6x^2+9x-16=0 are x=(-9+sqrt(465))/(12),x=(-9-sqrt(465))/(12)
Find the zeros of 6x^2+9x-16=0
The zeros of 6x^2+9x-16=0 are x=(-9+sqrt(465))/(12),x=(-9-sqrt(465))/(12)