What are the solutions to the equation X^2+10X+21=0 ?

The solutions to the equation X^2+10X+21=0 are X=-3,X=-7

Find the zeros of X^2+10X+21=0

The zeros of X^2+10X+21=0 are X=-3,X=-7

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X^{2} + 10 X + 21 = 0

X = - 3, X = - 7

Solution steps

X^{2} + 10 X + 21 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 21 = 4

X_{1, 2} = \frac{- 10 \pm 4}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 10 + 4}{2 \cdot 1}, X_{2} = \frac{- 10 - 4}{2 \cdot 1}

X = \frac{- 10 + 4}{2 \cdot 1} : - 3

X = \frac{- 10 - 4}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

X = - 3, X = - 7

- 16 x^{2} + 272 x + 204 = 0

x, 26406.25 = (25 - 2 x) (1000 + 50 x)

y^{2} + 7 y + 6 = 0

3 (x + 5)^{2} = 0

2 n^{2} - 11 n - 13 = 0

What are the solutions to the equation X^2+10X+21=0 ?
The solutions to the equation X^2+10X+21=0 are X=-3,X=-7
Find the zeros of X^2+10X+21=0
The zeros of X^2+10X+21=0 are X=-3,X=-7