What are the solutions to the equation x^2+x-6=2x ?

The solutions to the equation x^2+x-6=2x are x=3,x=-2

Find the zeros of x^2+x-6=2x

The zeros of x^2+x-6=2x are x=3,x=-2

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x^{2} + x - 6 = 2 x

x = 3, x = - 2

Solution steps

x^{2} + x - 6 = 2 x

Move

2 x

to the left side

x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

x = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

x = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

20 x^{2} - 7 x - 3 = 0

50 x^{2} = 18

x, z = 3 x^{2} - 12 x + 2 y^{3} + 3 y^{2} - 12 y

0 = 18 x^{2} - 18 x - 108

y^{2} = \frac{1}{4}

What are the solutions to the equation x^2+x-6=2x ?
The solutions to the equation x^2+x-6=2x are x=3,x=-2
Find the zeros of x^2+x-6=2x
The zeros of x^2+x-6=2x are x=3,x=-2