What are the solutions to the equation (x+4)^2+7=0 ?

The solutions to the equation (x+4)^2+7=0 are x=sqrt(7)i-4,x=-sqrt(7)i-4

Find the zeros of (x+4)^2+7=0

The zeros of (x+4)^2+7=0 are x=sqrt(7)i-4,x=-sqrt(7)i-4

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(x + 4)^{2} + 7 = 0

x = 7 i - 4, x = - 7 i - 4

Solution steps

(x + 4)^{2} + 7 = 0

Move

7

to the right side

(x + 4)^{2} = - 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = - 7 : x = 7 i - 4

Solve

x + 4 = - - 7 : x = - 7 i - 4

The solutions to the quadratic equation are:

x = 7 i - 4, x = - 7 i - 4

3 t^{2} - 60 t = 0

m^{2} + 3 m + 6 = 0

V, P = \frac{V ^{2}}{R}

3 y^{2} - 36 = 0

x^{2} + 2 x = 143

What are the solutions to the equation (x+4)^2+7=0 ?
The solutions to the equation (x+4)^2+7=0 are x=sqrt(7)i-4,x=-sqrt(7)i-4
Find the zeros of (x+4)^2+7=0
The zeros of (x+4)^2+7=0 are x=sqrt(7)i-4,x=-sqrt(7)i-4