What are the solutions to the equation 2x^2-14x+12=0 ?

The solutions to the equation 2x^2-14x+12=0 are x=6,x=1

Find the zeros of 2x^2-14x+12=0

The zeros of 2x^2-14x+12=0 are x=6,x=1

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2 x^{2} - 14 x + 12 = 0

x = 6, x = 1

Solution steps

2 x^{2} - 14 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 \cdot 12 = 10

x_{1, 2} = \frac{- ( - 14 ) \pm 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 10}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 10}{2 \cdot 2}

x = \frac{- ( - 14 ) + 10}{2 \cdot 2} : 6

x = \frac{- ( - 14 ) - 10}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = 6, x = 1

4 x^{2} + 27 x - 40 = 0

x^{2} + 20 x + 100 = 81

3 (g - 1)^{2} + 2 = 0

x^{2} - 10 x + 9 = 0

9 u^{2} = 30 u - 25

What are the solutions to the equation 2x^2-14x+12=0 ?
The solutions to the equation 2x^2-14x+12=0 are x=6,x=1
Find the zeros of 2x^2-14x+12=0
The zeros of 2x^2-14x+12=0 are x=6,x=1