What are the solutions to the equation 3(g-1)^2+2=0 ?

The solutions to the equation 3(g-1)^2+2=0 are g=isqrt(2/3)+1,g=-isqrt(2/3)+1

Find the zeros of 3(g-1)^2+2=0

The zeros of 3(g-1)^2+2=0 are g=isqrt(2/3)+1,g=-isqrt(2/3)+1

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3 (g - 1)^{2} + 2 = 0

g = i \frac{2}{3} + 1, g = - i \frac{2}{3} + 1

Solution steps

3 (g - 1)^{2} + 2 = 0

Move

2

to the right side

3 (g - 1)^{2} = - 2

Divide both sides by

3

(g - 1)^{2} = - \frac{2}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

g - 1 = - \frac{2}{3} : g = i \frac{2}{3} + 1

Solve

g - 1 = - - \frac{2}{3} : g = - i \frac{2}{3} + 1

The solutions to the quadratic equation are:

g = i \frac{2}{3} + 1, g = - i \frac{2}{3} + 1

x^{2} - 10 x + 9 = 0

9 u^{2} = 30 u - 25

x (6 x + 3) = 0

2 x^{2} + 5 x - 8 = \frac{5}{2} x + 20

x^{2} - 28 x + 16 = 0

What are the solutions to the equation 3(g-1)^2+2=0 ?
The solutions to the equation 3(g-1)^2+2=0 are g=isqrt(2/3)+1,g=-isqrt(2/3)+1
Find the zeros of 3(g-1)^2+2=0
The zeros of 3(g-1)^2+2=0 are g=isqrt(2/3)+1,g=-isqrt(2/3)+1