What are the solutions to the equation solvefor x,x^2+3x-2=0 ?

The solutions to the equation solvefor x,x^2+3x-2=0 are x=(-3+sqrt(17))/2 ,x=(-3-sqrt(17))/2

Find the zeros of solvefor x,x^2+3x-2=0

The zeros of solvefor x,x^2+3x-2=0 are x=(-3+sqrt(17))/2 ,x=(-3-sqrt(17))/2

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x, x^{2} + 3 x - 2 = 0

x = \frac{- 3 + 17}{2}, x = \frac{- 3 - 17}{2}

Decimal Notation

x = 0.56155 \dots, x = - 3.56155 \dots

Solution steps

x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 2) = 17

x_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 17}{2 \cdot 1}, x_{2} = \frac{- 3 - 17}{2 \cdot 1}

x = \frac{- 3 + 17}{2 \cdot 1} : \frac{- 3 + 17}{2}

x = \frac{- 3 - 17}{2 \cdot 1} : \frac{- 3 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 17}{2}, x = \frac{- 3 - 17}{2}

(x + 4)^{2} + 50 = 0

k^{2} - 7 k + 6 = 0

(- 1 - x) (5 - x) + 9 = 0

5 (2 x^{2} + 32) = 0

x, 8 x^{2} - 8 x = (4 y - 7)^{3}

What are the solutions to the equation solvefor x,x^2+3x-2=0 ?
The solutions to the equation solvefor x,x^2+3x-2=0 are x=(-3+sqrt(17))/2 ,x=(-3-sqrt(17))/2
Find the zeros of solvefor x,x^2+3x-2=0
The zeros of solvefor x,x^2+3x-2=0 are x=(-3+sqrt(17))/2 ,x=(-3-sqrt(17))/2