What are the solutions to the equation y^2+9y-22=0 ?

The solutions to the equation y^2+9y-22=0 are y=2,y=-11

Find the zeros of y^2+9y-22=0

The zeros of y^2+9y-22=0 are y=2,y=-11

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y^{2} + 9 y - 22 = 0

y = 2, y = - 11

Solution steps

y^{2} + 9 y - 22 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 22 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 22) = 13

y_{1, 2} = \frac{- 9 \pm 13}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 9 + 13}{2 \cdot 1}, y_{2} = \frac{- 9 - 13}{2 \cdot 1}

y = \frac{- 9 + 13}{2 \cdot 1} : 2

y = \frac{- 9 - 13}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

y = 2, y = - 11

x^{2} - 2021 x + 7 (x - 2021) = 0

p^{2} - 2 p - 24 = 0

1450 \frac{V ^{2}}{24} = 1450 \cdot 9.8

5 x^{2} + 13 x - 28 = 0

2 x^{2} + 8 x - 3 = 0

What are the solutions to the equation y^2+9y-22=0 ?
The solutions to the equation y^2+9y-22=0 are y=2,y=-11
Find the zeros of y^2+9y-22=0
The zeros of y^2+9y-22=0 are y=2,y=-11