What are the solutions to the equation p^2-2p-24=0 ?

The solutions to the equation p^2-2p-24=0 are p=6,p=-4

Find the zeros of p^2-2p-24=0

The zeros of p^2-2p-24=0 are p=6,p=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

p^{2} - 2 p - 24 = 0

p = 6, p = - 4

Solution steps

p^{2} - 2 p - 24 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 24) = 10

p_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 1}, p_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 1}

p = \frac{- ( - 2 ) + 10}{2 \cdot 1} : 6

p = \frac{- ( - 2 ) - 10}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

p = 6, p = - 4

1450 \frac{V ^{2}}{24} = 1450 \cdot 9.8

5 x^{2} + 13 x - 28 = 0

2 x^{2} + 8 x - 3 = 0

2 = 1 + x^{2}

5^{2} + b^{2} = 1 1^{2}

What are the solutions to the equation p^2-2p-24=0 ?
The solutions to the equation p^2-2p-24=0 are p=6,p=-4
Find the zeros of p^2-2p-24=0
The zeros of p^2-2p-24=0 are p=6,p=-4