What are the solutions to the equation 2x^2-9x+2=-1 ?

The solutions to the equation 2x^2-9x+2=-1 are x=(9+sqrt(57))/4 ,x=(9-sqrt(57))/4

Find the zeros of 2x^2-9x+2=-1

The zeros of 2x^2-9x+2=-1 are x=(9+sqrt(57))/4 ,x=(9-sqrt(57))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 9 x + 2 = - 1

x = \frac{9 + 57}{4}, x = \frac{9 - 57}{4}

Decimal Notation

x = 4.13745 \dots, x = 0.36254 \dots

Solution steps

2 x^{2} - 9 x + 2 = - 1

Move

1

to the left side

2 x^{2} - 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 \cdot 3 = 57

x_{1, 2} = \frac{- ( - 9 ) \pm 57}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 57}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 57}{2 \cdot 2}

x = \frac{- ( - 9 ) + 57}{2 \cdot 2} : \frac{9 + 57}{4}

x = \frac{- ( - 9 ) - 57}{2 \cdot 2} : \frac{9 - 57}{4}

The solutions to the quadratic equation are:

x = \frac{9 + 57}{4}, x = \frac{9 - 57}{4}

x^{2} - \frac{5}{3} x - 26 = 0

y, 2 y^{2} - x^{2} + x^{3} y = 2

0.000006 x^{2} - 0.02 x + 25 = 30

- x^{2} - 18 x - 81 = 0

t, (t - h)^{2} = \frac{8}{5}

What are the solutions to the equation 2x^2-9x+2=-1 ?
The solutions to the equation 2x^2-9x+2=-1 are x=(9+sqrt(57))/4 ,x=(9-sqrt(57))/4
Find the zeros of 2x^2-9x+2=-1
The zeros of 2x^2-9x+2=-1 are x=(9+sqrt(57))/4 ,x=(9-sqrt(57))/4