What are the solutions to the equation (t^2+1)=0 ?

The solutions to the equation (t^2+1)=0 are t=i,t=-i

Find the zeros of (t^2+1)=0

The zeros of (t^2+1)=0 are t=i,t=-i

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(t^{2} + 1) = 0

t = i, t = - i

Solution steps

(t^{2} + 1) = 0

t^{2} + 1 = 0

Move

1

to the right side

t^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = - 1, t = - - 1

- 1 = i

- - 1 = - i

t = i, t = - i

y, (y + 1)^{2} = 4 (x + 1)^{3}

x^{2} - 8 x + 22

x^{2} - 8 x + 20

x^{2} - 8 x + 21

k^{2} + 24 k + 144 = 0

What are the solutions to the equation (t^2+1)=0 ?
The solutions to the equation (t^2+1)=0 are t=i,t=-i
Find the zeros of (t^2+1)=0
The zeros of (t^2+1)=0 are t=i,t=-i