What are the solutions to the equation 2x^2+20x-7=0 ?

The solutions to the equation 2x^2+20x-7=0 are x=(-10+sqrt(114))/2 ,x=-(10+sqrt(114))/2

Find the zeros of 2x^2+20x-7=0

The zeros of 2x^2+20x-7=0 are x=(-10+sqrt(114))/2 ,x=-(10+sqrt(114))/2

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2 x^{2} + 20 x - 7 = 0

x = \frac{- 10 + 114}{2}, x = - \frac{10 + 114}{2}

Decimal Notation

x = 0.33853 \dots, x = - 10.33853 \dots

Solution steps

2 x^{2} + 20 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 (- 7) = 2114

x_{1, 2} = \frac{- 20 \pm 2 114}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 2 114}{2 \cdot 2}, x_{2} = \frac{- 20 - 2 114}{2 \cdot 2}

x = \frac{- 20 + 2 114}{2 \cdot 2} : \frac{- 10 + 114}{2}

x = \frac{- 20 - 2 114}{2 \cdot 2} : - \frac{10 + 114}{2}

The solutions to the quadratic equation are:

x = \frac{- 10 + 114}{2}, x = - \frac{10 + 114}{2}

- 3 x^{2} - 4 x + 12 = 0

y^{2} - 196 = 0

3 r^{2} - 16 r - 2 = 0

2 x^{2} - 21 x + 40 = 0

x^{2} - 5.1 x + 6.3 = 0

What are the solutions to the equation 2x^2+20x-7=0 ?
The solutions to the equation 2x^2+20x-7=0 are x=(-10+sqrt(114))/2 ,x=-(10+sqrt(114))/2
Find the zeros of 2x^2+20x-7=0
The zeros of 2x^2+20x-7=0 are x=(-10+sqrt(114))/2 ,x=-(10+sqrt(114))/2