What are the solutions to the equation 3p^2+2p-96=0 ?

The solutions to the equation 3p^2+2p-96=0 are p= 16/3 ,p=-6

Find the zeros of 3p^2+2p-96=0

The zeros of 3p^2+2p-96=0 are p= 16/3 ,p=-6

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3 p^{2} + 2 p - 96 = 0

p = \frac{16}{3}, p = - 6

Decimal Notation

p = 5.33333 \dots, p = - 6

Solution steps

3 p^{2} + 2 p - 96 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 96 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 96) = 34

p_{1, 2} = \frac{- 2 \pm 34}{2 \cdot 3}

Separate the solutions

p_{1} = \frac{- 2 + 34}{2 \cdot 3}, p_{2} = \frac{- 2 - 34}{2 \cdot 3}

p = \frac{- 2 + 34}{2 \cdot 3} : \frac{16}{3}

p = \frac{- 2 - 34}{2 \cdot 3} : - 6

The solutions to the quadratic equation are:

p = \frac{16}{3}, p = - 6

x^{2} - 18 x + 8 = 0

r, S = 2 π r (r + h)

p^{2} + 3 p - 9 = 0

(x) (x + 1) = 156

x^{2} - 10 x = 50

What are the solutions to the equation 3p^2+2p-96=0 ?
The solutions to the equation 3p^2+2p-96=0 are p= 16/3 ,p=-6
Find the zeros of 3p^2+2p-96=0
The zeros of 3p^2+2p-96=0 are p= 16/3 ,p=-6