What are the solutions to the equation p^2+3p-9=0 ?

The solutions to the equation p^2+3p-9=0 are p=(-3+3sqrt(5))/2 ,p=(-3-3sqrt(5))/2

Find the zeros of p^2+3p-9=0

The zeros of p^2+3p-9=0 are p=(-3+3sqrt(5))/2 ,p=(-3-3sqrt(5))/2

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p^{2} + 3 p - 9 = 0

p = \frac{- 3 + 3 5}{2}, p = \frac{- 3 - 3 5}{2}

Decimal Notation

p = 1.85410 \dots, p = - 4.85410 \dots

Solution steps

p^{2} + 3 p - 9 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 9) = 35

p_{1, 2} = \frac{- 3 \pm 3 5}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 3 + 3 5}{2 \cdot 1}, p_{2} = \frac{- 3 - 3 5}{2 \cdot 1}

p = \frac{- 3 + 3 5}{2 \cdot 1} : \frac{- 3 + 3 5}{2}

p = \frac{- 3 - 3 5}{2 \cdot 1} : \frac{- 3 - 3 5}{2}

The solutions to the quadratic equation are:

p = \frac{- 3 + 3 5}{2}, p = \frac{- 3 - 3 5}{2}

(x) (x + 1) = 156

x^{2} - 10 x = 50

12 x^{2} + 8 x + 1 = 0

x, x^{2} + 45 k^{2} = 18 k x

x, 2 x^{2} + 12 x + 4 = 0

What are the solutions to the equation p^2+3p-9=0 ?
The solutions to the equation p^2+3p-9=0 are p=(-3+3sqrt(5))/2 ,p=(-3-3sqrt(5))/2
Find the zeros of p^2+3p-9=0
The zeros of p^2+3p-9=0 are p=(-3+3sqrt(5))/2 ,p=(-3-3sqrt(5))/2