What are the solutions to the equation (m^2+2m+2)=0 ?

The solutions to the equation (m^2+2m+2)=0 are m=-1+i,m=-1-i

Find the zeros of (m^2+2m+2)=0

The zeros of (m^2+2m+2)=0 are m=-1+i,m=-1-i

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(m^{2} + 2 m + 2) = 0

m = - 1 + i, m = - 1 - i

Solution steps

(m^{2} + 2 m + 2) = 0

Refine

m^{2} + 2 m + 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 2 : 2 i

m_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 2 i}{2 \cdot 1}, m_{2} = \frac{- 2 - 2 i}{2 \cdot 1}

m = \frac{- 2 + 2 i}{2 \cdot 1} : - 1 + i

m = \frac{- 2 - 2 i}{2 \cdot 1} : - 1 - i

The solutions to the quadratic equation are:

m = - 1 + i, m = - 1 - i

(x - 3)^{2} + 1 = 2 x - 5

\frac{1}{4} (2 A) + 2 A x + B + A x^{2} + B x + C = x^{2} - 2 x

0.48 x^{2} - 1.88 x - 1.68 = 0

7 x^{2} - 3 x + j = 0

z^{2} - 10 z = - 5

What are the solutions to the equation (m^2+2m+2)=0 ?
The solutions to the equation (m^2+2m+2)=0 are m=-1+i,m=-1-i
Find the zeros of (m^2+2m+2)=0
The zeros of (m^2+2m+2)=0 are m=-1+i,m=-1-i